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4x^2-2-2x=x-5
We move all terms to the left:
4x^2-2-2x-(x-5)=0
We get rid of parentheses
4x^2-2x-x+5-2=0
We add all the numbers together, and all the variables
4x^2-3x+3=0
a = 4; b = -3; c = +3;
Δ = b2-4ac
Δ = -32-4·4·3
Δ = -39
Delta is less than zero, so there is no solution for the equation
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